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4/100 how to validate numbers like this dynamically

+1 vote
51 views
asked in Programming by anonymous
the number 4 is changing every time ,how to validate dynamically.

1 Answer

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answered by Himanshu Expert (5,940 points)

String strID1 = driver.findElement(By.xpath("Xpath here");
                        String[] parts = strID1.split("/");
                        String part1 = parts[0];

Now you can validate part1, in your case 4/100.

part1 will return 4. I hope you got my point.

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